[openpgp] Be more resistant against invalid keys
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13
openpgp/backend/util.py
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13
openpgp/backend/util.py
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from __future__ import annotations
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def parse_uid(uid: str, compat=False) -> str:
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if uid.startswith('xmpp:'):
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return uid[5:]
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# Compat with uids of form "Name <xmpp:my@jid.com>"
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if compat and '<xmpp:' in uid and uid.endswith('>'):
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return uid[:-1].split('<xmpp:', maxsplit=1)[1]
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raise ValueError('Uknown UID format: %s' % uid)
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